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-1.5q^2+6q-2.5=0
a = -1.5; b = 6; c = -2.5;
Δ = b2-4ac
Δ = 62-4·(-1.5)·(-2.5)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{21}}{2*-1.5}=\frac{-6-\sqrt{21}}{-3} $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{21}}{2*-1.5}=\frac{-6+\sqrt{21}}{-3} $
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